Answer :
Thanks for asking the question.
The range of projectile is given by the formula:
R = vi^2sin2@/g
According to this formula the range of projectile is directly propotional to the square of the initial velocity. So when the initial velocity is doubled the range of projectile becomes four times as per the formula where as the angle of projectile remains un changed.
Hope it helps.
The range of projectile is given by the formula:
R = vi^2sin2@/g
According to this formula the range of projectile is directly propotional to the square of the initial velocity. So when the initial velocity is doubled the range of projectile becomes four times as per the formula where as the angle of projectile remains un changed.
Hope it helps.
Explanation:
Horizontal Range of projection
u²sin²Ø
R = ————
g
R directly proportional u²
when inital velocity 'u' is doubled
R' is range after the initial velocity is doubled which is " u' "
then,
u'=2
R'/R=( u')/u²
R'=((2u)²/u²) x R
u²/u² is cancelled out which became 1
therefore..,
R'=2² x R
R'=4R
R as became four times as doubled initial velocity ,
when angle remains unchanged