sherinmohan
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SOLVE: 1) DIVIDE 72 INTO TWO PARTS SO THAT THE LARGER PART EXCEEDS THE SMALLER PART BY 12. FIND BOTH THE PARTS.

Answer :

let smaller part= x
larger part= 72-x
by hypothesis, we have
72-x-x=12
-2x+72-12=0
-2x+60=0
-2x=-60
x=30
smaller part=30
larger part=72-30=42
Samz
Let the first part be x and second part be x+12
according to the question
x + x + 12  =  72
2x + 12 = 72
2x = 72-12
2x = 60
x  =  30
so first part = x = 30
second part = x + 12 = 30 + 12 = 42

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