Answer :
Solution:-
Total surface area of the cuboid = 2(LB + BH + HL)
= 2(1*2 + 2*1.5 + 1.5*1)
= 2(2 + 3 + 1.5)
= 2*6.5
Total surface area = 13 sq m
Now, the bottom of the cabinet is not to be painted, so area of the bottom must be deducted from the total surface area.
Area of the bottom part of the cabinet = 1*2
= 2 sq m
Surface area of the cabinet covered by paint except the bottom part = 13 - 2
= 11 sq m
Answer.
Total surface area of the cuboid = 2(LB + BH + HL)
= 2(1*2 + 2*1.5 + 1.5*1)
= 2(2 + 3 + 1.5)
= 2*6.5
Total surface area = 13 sq m
Now, the bottom of the cabinet is not to be painted, so area of the bottom must be deducted from the total surface area.
Area of the bottom part of the cabinet = 1*2
= 2 sq m
Surface area of the cabinet covered by paint except the bottom part = 13 - 2
= 11 sq m
Answer.
Solution:
l = 2 m, b = 1.5 m, h = 1 m
Area of the surface to be painted = Total surface area of box – Area of base of box
= 2 [lb + bh + hl] – lb
= 2[2 × 1.5 + 1.5 × 1 + 1 × 2] – 2 × 1
= 2[3 + 1.5 + 2] – 2
= 2[6.5] – 2
= 13 – 2
= 11 m2
Hence, the required area = 11 m2.