Answer :
In a parallelogram ABCD, AB= CD, BC=AD , angles A = C, B = D
and A+B = C+D = 180 deg
1. perimeter = 2AB +2 BC = 21 cm, AB = 4.5 cm
BC = 12/2 = 6 cm. CD=4.5 cm, AD = 6 cm
2. A/D = 2/3 => A = 2 D/3 => A+D = D+2D/3 = 5D/3 = A+B = 180
D = 180*3/5 = 108 deg A = 72 deg = C B = D = 108 deg
3. A = 180 - 68 = 112 deg, C = A = 112 deg, D = B = 68 deg
and A+B = C+D = 180 deg
1. perimeter = 2AB +2 BC = 21 cm, AB = 4.5 cm
BC = 12/2 = 6 cm. CD=4.5 cm, AD = 6 cm
2. A/D = 2/3 => A = 2 D/3 => A+D = D+2D/3 = 5D/3 = A+B = 180
D = 180*3/5 = 108 deg A = 72 deg = C B = D = 108 deg
3. A = 180 - 68 = 112 deg, C = A = 112 deg, D = B = 68 deg