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Answered

sole by using quadratic formula 
x2+1/x=3         x is not =0

root 3 square  +10x-  8root3=0

x2-x+1=0

x2-x-a[a+1}=0




plz friends help me i am asking help bcoz we have a  bad faculty in oys school am blak


Answer :

ax²+bx+c=0 is a quadratic equation for x≠0 Here, x=(-b±√{b²-4ac})/2a When you substitute the corresponding values you get the answers. 1.x²-3x+1=0 here, a=1 b=-3 c=1 putting these values in the above formula you get x=(3±√5)/2. 2.a=√3 b=10 c=-8√3 hence x=11/2 or -17/2 3.x=(1±√-3)/2