"Difference of the terms of this series is in A.P.
2+1 = 3,
2+1+3 = 6,
2+1+3+5= 11,
2+1+3+5+7 = 18 and so on.
Sn = n/2[ 2a + ( n - 1 ) d ]
Here a = first term = 1 , n = number of term = 49 and d = common difference = 2 , So
Sn = 49/2[ 2( 1 ) + ( 49 - 1 ) 2 ] = 49 [ 1 + ( 49 - 1 ) ] = 492
Hence, Sum of 49 terms of series 1,3,5,7,9,11,.. = 492
Now, to get the T50 term.. add 2+ sum of the 1+3+5+7+..+97
T50 of series 2 + 3 + 6 + 11 + 18+....... = 2 + 492 = 2 + 2401 = 2403
"
Answer:
t50=2403
Step-by-step explanation:
2+0²,2+1²,2+2²,2+3²,2+4²
tn= (n-1)²+2
t50= (50-1)²+2
t50= (49)²+2
t50=2403
