Answer :
Hi ,
1 , 2 , 3 , 4 , 5 are first five natural
numbers .
To find the least positive integer divisible
by 1 , 2 , 3 , 4 , 5 we have to find L C M of
these numbers ,
2 | 1 , 2 , 3 , 4 , 5
______________
1 , 1 , 3 , 2 , 5
Therefore L C M ( 1 ,2 , 3 ,4 , 5 ) = 2 × 3 × 2 × 5
= 60
60 is the least positive integer divisible by
1 st five natural numbers .
I hope this helps you.
:)
1 , 2 , 3 , 4 , 5 are first five natural
numbers .
To find the least positive integer divisible
by 1 , 2 , 3 , 4 , 5 we have to find L C M of
these numbers ,
2 | 1 , 2 , 3 , 4 , 5
______________
1 , 1 , 3 , 2 , 5
Therefore L C M ( 1 ,2 , 3 ,4 , 5 ) = 2 × 3 × 2 × 5
= 60
60 is the least positive integer divisible by
1 st five natural numbers .
I hope this helps you.
:)
Answer:
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Secondary SchoolMath 5+3 pts
find the least positive integer divisible by 1st five natural numbers
Report by Harshaalfa 04.11.2014
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Ganeshsaraswat09 · Helping Hand
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mysticd
Mysticd Maths AryaBhatta
Hi ,
1 , 2 , 3 , 4 , 5 are first five natural
numbers .
To find the least positive integer divisible
by 1 , 2 , 3 , 4 , 5 we have to find L C M of
these numbers ,
2 | 1 , 2 , 3 , 4 , 5
______________
1 , 1 , 3 , 2 , 5
Therefore L C M ( 1 ,2 , 3 ,4 , 5 ) = 2 × 3 × 2 × 5
= 60
60 is the least positive integer divisible by
1 st five natural numbers .
I hope this helps you.