17-03-2014
Math

Answered

sin 2Θ = cos 3Θ
Then Θ = ?

Answer :

maryjessicka maryjessicka

17-03-2014

sin2Ф = cos(90-2Ф)
so, sin2Ф = cos3Ф
⇒ cos(90-2Ф) = cos3Ф
⇒90-2Ф = 3Ф
⇒3Ф+2Ф = 90
⇒ 5Ф = 90
⇒Ф = 18

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