Answer :
tan theta = Perpendicular/Base = 3/4
by using Pythagoras theorem
AC²=AB²+BC²
5²=3²+BC²
5²-3²=BC²
25-9=BC²
16=BC²
BC= under root 16
BC=4
tan theta = Perpendicular/Base = 3/4
by using Pythagoras theorem
AC²=AB²+BC²
5²=3²+BC²
5²-3²=BC²
25-9=BC²
16=BC²
BC= under root 16
BC=4