Answer :

For any pair of linear equation

a₁ x + b₁ y + c₁ = 0

a₂ x + b₂ y + c₂ = 0

a) a₁/a₂ ≠ b₁/b₂ (Intersecting Lines)

b) a₁/a₂ = b₁/b₂ = c₁/c₂ (Coincident Lines)

c) a₁/a₂ = b₁/b₂ ≠ c₁/c₂ (Parallel Lines)

(i) 5x - 4y + 8 = 0 and 7x + 6 - 9 = 0

a₁ = 5, b₁ = - 4, c₁ = 8

a₂ = 7, b₂ = 6, c₂ = - 9

a₁/a₂ = 5/7...(1)

b₁/b₂ = -4/6 = -2/3...(2)

From (1) and (2)

a₁/a₂ ≠ b₁/b₂

Therefore, they are intersecting lines at a point.

(ii) 9x + 3y + 12 = 0 and 18x + 6y + 24 = 0

a₁ = 9, b₁ = 3, c₁ = 12

a₂ = 18, b₂ = 6, c₂ = 24

a₁/a₂ = 9/18 = 1/2...(1)

b₁/b₂ = 3/6 = 1/2...(2)

c₁/c₂ = 12/24 = 1/2...(3)

From (1), (2) and (3)

a₁/a₂ = b₁/b₂ = c₁/c₂= 1/2

Therefore, they are coincident lines.

(iii) 6x – 3y + 10 = 0 and 2x – y + 9 = 0

a₁ = 6, b₁ = - 3, c₁ = 10

a₂ = 2, b₂ = - 1, c₂ = 9

a₁/a₂ = 6/2 = 3...(1)

b₁/b₂ = - 3/(- 1 ) = 3...(2)

c₁/c₂ = 10/9...(3)

From (1), (2) and (3)

a₁/a₂ = b₁/b₂ ≠ c₁/c₂

Therefore, they are parallel lines.

Answer:

coincident lines

Step-by-step explanation:

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