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6. The velocity-time graph of a ball is given below.
Velocity+
10 m/s
5 m/s
B
D
E
0 5 10 15 20 25 30 35 40
What is the acceleration of the ball
(i) During first 10 s?
Time (s)
(ii) Between 10 s and 35 s?
(iii) During 35 s to 40 s?

Answer :

(i) During the first 10 seconds:

Acceleration = Change in velocity / Change in time

From the graph, the velocity changes from 0 m/s to 10 m/s in the first 10 seconds.

So, the change in velocity = 10 m/s - 0 m/s = 10 m/s

The change in time = 10 s - 0 s = 10 s

Acceleration = 10 m/s / 10 s = 1 m/s²

(ii) Between 10 seconds and 35 seconds:

Acceleration = Change in velocity / Change in time

From the graph, the velocity changes from 10 m/s to 0 m/s in the interval from 10 s to 35 s.

So, the change in velocity = 0 m/s - 10 m/s = -10 m/s (negative because the velocity decreases)

The change in time = 35 s - 10 s = 25 s

Acceleration = -10 m/s / 25 s = -0.4 m/s²

(iii) During 35 s to 40 s:

Acceleration = Change in velocity / Change in time

From the graph, the velocity remains constant at 0 m/s during this interval.

So, the change in velocity = 0 m/s - 0 m/s = 0 m/s

The change in time = 40 s - 35 s = 5 s

Acceleration = 0 m/s / 5 s = 0 m/s²

So, the accelerations during the different time intervals are:

(i) During the first 10 seconds: 1 m/s²

(ii) Between 10 seconds and 35 seconds: -0.4 m/s²

(iii) During 35 seconds to 40 seconds: 0 m/s²

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