Answer :
Answer:
The molarity of the HCl solution can be calculated using the given information.
Given:
- Concentration of HCl solution = 70% w/v (i.e., 70 g HCl in 100 mL solution)
- Density of the solution = 1.17 g/mL
First, let's find the mass of HCl in 100 mL of the solution:
\[ \text{Mass of HCl} = \text{Concentration} \times \text{Volume} \]
\[ \text{Mass of HCl} = 70 \text{ g/100 mL} \times 100 \text{ mL} = 70 \text{ g} \]
Next, determine the volume of 100 mL of the solution in liters:
\[ \text{Volume of solution} = 100 \text{ mL} \times \frac{1 \text{ L}}{1000 \text{ mL}} = 0.1 \text{ L} \]
Now, calculate the molarity using the formula:
\[ \text{Molarity} = \frac{\text{Moles of solute}}{\text{Volume of solution in liters}} \]
First, find the moles of HCl:
\[ \text{Moles of HCl} = \frac{\text{Mass of HCl}}{\text{Molar mass of HCl}} \]
The molar mass of HCl (hydrochloric acid) is approximately 36.5 g/mol.
\[ \text{Moles of HCl} = \frac{70 \text{ g}}{36.5 \text{ g/mol}} \approx 1.92 \text{ mol} \]
Finally, calculate the molarity:
\[ \text{Molarity} = \frac{1.92 \text{ mol}}{0.1 \text{ L}} = 19.2 \text{ mol/L} \]
So, the molarity of the HCl solution is approximately 19.2 mol/L. The closest option provided is (c) 19.17 Mol/L.
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