Answer:
## **<ins>Short Answer : </ins>**
The molarity of the solution is 0.48mol / L
## **<ins>Detailed Answer: </ ins >**
Step 1: Calculate the number of moles of sodium chloride in 120 g.
The molar mass of sodium chloride (NaCl) is 58.44g / m * ol Therefore, the number of moles of sodium chloride in 120 g is: n = m/M = (120g)/(58.44g / m * ol) = 2.05mol
Step 2: Calculate the volume of the solution in
liters.
The volume of the solution is 2.50 L.
Step 3: Calculate the molarity of the solution. The molarity of the solution is defined as the number of moles of solute per liter of solution. Therefore, the molarity of the solution is: M = n/V = (2.05mol)/(2.5L) = 0.82mol / L Therefore, the molarity of the solution is 0.82 mol / L
