Answer :
Answer:
Given,
u
=
O
,
a
=
4
m
s
−
2
Distance travelled in 5th second
s
n
=
u
+
1
2
a
(
2
n
−
1
)
s
5
=
0
+
1
2
×
4
(
2
×
5
−
1
)
=
1
2
×
4
(
9
)
=
36
2
=
18
m
Answer:
14 metres
Explanation:
To understand this question you can first draw a rough speed-time graph as acceleration is the gradient in this type of graph. Our gradient will be as how it is shown in the image.
To find the distance covered, we have to find the area. Since it is a triangle we can use:
[tex]\frac{1}{2} *b*h[/tex]
our base is the time (7 seconds)
our height will be acceleration(4 m/[tex]s^{2}[/tex])
[tex]\frac{1}{2}*4*7[/tex]
Therefore the answer is 14 m
