Answer:
Yes, that's correct! If the last \( p \) digits of a binary number are zeros, then the number is divisible by \( 2^p \). This is because in binary representation, each digit corresponds to a power of 2.
For example, let's say we have the binary number \( 11010000 \). The last three digits are zeros, indicating that the number is divisible by \( 2^3 = 8 \). In decimal, this binary number is 208, which is indeed divisible by 8.
Similarly, for any binary number, if the last \( p \) digits are zeros, it means the number is divisible by \( 2^p \).
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