Answer :
Answer:
For an expression of the form (1+x)n, where 'n' can be a negative integer or fraction and the absolute value of 'x' is less than 1, the expansion can be represented as: (1+x)n = 1 + nx + n(n-1)x2/2! + n(n-1)(n-2)x3/3!
Step-by-step explanation:
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