Answer :
Step-by-step explanation:
To find the value of the expression \( x^2(1+y^2 - 2xy) \) when \( x = -1 \) and \( y = -2 \), substitute the values into the expression:
\( x^2(1+y^2 - 2xy) \)
\( = (-1)^2(1+(-2)^2 - 2(-1)(-2)) \)
\( = (1)(1+4 - 4) \)
\( = 1(1) \)
\( = 1 \)
So, when \( x = -1 \) and \( y = -2 \), the value of the expression is 1.