Answer :
Answer:
Let C.P of tea set =x and lemon set =y
ATP, 15100×y−5100×x=70
⇒3y−x=70×20
⇒3y−x=1400⟶(1)
Again,
5100×x+10100×y=130
⇒x+2y=130×20
⇒x+2y=2600⟶(2)
Substituting x from equation (1) in equation (2)
3y−1400+2y=2600
⇒5y=4000
⇒y=800
Answer:
Cost price of a tea set is Rs 1000 and cost price of a lemon set is Rs 800.
Step-by-step explanation:
Let assume that cost price of a tea set and lemon set be Rs x and Rs y respectively.
According to statement, on selling a tea set at 10% loss and a lemon set at 20% gain.
[tex]\sf\: - \dfrac{10x}{100} + \dfrac{20y}{100} = 60 \\ [/tex]
[tex]\sf\: - \dfrac{x}{10} + \dfrac{2y}{10} = 60 \\ [/tex]
[tex]\implies\sf\: - x + 2y = 600 - - - (1) \\ [/tex]
According to statement again, a shopkeeper gains Rs 10, if he sells at 5% gain and lemon set at 5% loss, he gains Rs 10 .
[tex]\sf\: \dfrac{5x}{100} - \dfrac{5y}{100} = 10 \\ [/tex]
[tex]\sf\: \dfrac{x}{20} - \dfrac{y}{20} = 10 \\ [/tex]
[tex]\implies\sf\:x - y = 200 - - - (2) \\ [/tex]
On adding equation (1) and (2), we get
[tex]\implies\sf\:y = 800 \\ [/tex]
On substituting the value of x in (2), we get
[tex]\implies\sf\:x= 1000 \\ [/tex]
Hence, Cost price of a tea set is Rs 1000 and cost price of a lemon set is Rs 800.