Answered

the polynomial in X is X square + kx + 5 + K is constant at x = 2 the value of the polynomial is 15 what is the value of the polynomial at x = 5​

Answer :

akashadak1234567890

Answer:

42

Step-by-step explanation:

Let, f(x) = x² + kx + 5 + k

f(2) = 2² + k.2 + 5 + k

= 9 + 3k

by the question,

9 + 3k = 15

or, 3(k+3) = 15

or, k+3 = 5

or, k = 2

so, f(x) = x² + 2x + 5 + 2 = (x² +2x + 7)

now, f(5) = 5² + 2×5 + 7 = 25 + 10 + 7 = 42 [Ans.]

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