A die is thrown.
(i) A is the event of getting a number divisible by 2.
(ii) B is the event of getting a number less than 4.
(iii) C is the event of getting a prime number. Find the probability of each event.​

Answer :

Answer:The probability of each event is \(\frac{1}{2}\).

Step-by-step explanation:Find the number of favorable outcomes for event \(A\). \(A=\{2,4,6\}\) \(n(A)=3\) Step 2 Find the number of favorable outcomes for event \(B\). \(B=\{1,2,3\}\) \(n(B)=3\) Step 3 Find the number of favorable outcomes for event \(C\). \(C=\{2,3,5\}\) \(n(C)=3\) Step 4 Find the total number of possible outcomes. \(n(S)=6\) Step 5 Find the probability of event \(A\). \(P(A)=\frac{n(A)}{n(S)}\) \(P(A)=\frac{3}{6}\) \(P(A)=\frac{1}{2}\) Step 6 Find the probability of event \(B\). \(P(B)=\frac{n(B)}{n(S)}\) \(P(B)=\frac{3}{6}\) \(P(B)=\frac{1}{2}\) Step 7 Find the probability of event \(C\). \(P(C)=\frac{n(C)}{n(S)}\) \(P(C)=\frac{3}{6}\) \(P(C)=\frac{1}{2}\) Solution The probability of each event is \(\frac{1}{2}\).

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