A person has Rs.x and y paise with him. He spent Rs. 10.45 and was left with Rs.2y and 2x paise. What was the initial amount (in Rs.) with the person?

Answer :

Step-by-step explanation:

Let's solve this step by step.

1. Convert everything to paise to make it easier to calculate.

- We know 1 Rupee = 100 paise.

- So, Rs.x = x * 100 paise and y paise remains y paise.

2. The total amount before spending is \( x \times 100 + y \) paise.

3. After spending Rs.10.45 (which is 1045 paise), he is left with \( 2y + 2x \) paise.

4. Set up the equation based on the above information:

\( x \times 100 + y - 1045 = 2y + 2x \)

Now, let's solve this equation for x and y to find the initial amount.To find the values of x and y, we'll continue from the equation:

\( x \times 100 + y - 1045 = 2y + 2x \)

Let's simplify it:

\( 100x + y - 2x = 2y + 1045 \)

\( 98x - 2y = 1045 \)

Divide the entire equation by 2:

\( 49x - y = 522.5 \)

Now, we have one equation with two variables, which usually means we need more information to find a unique solution. However, since we're dealing with currency, and y represents paise, it cannot be a fraction. Therefore, y must be a multiple of 50 because \(522.5\) is not a whole number and we need to subtract something from it to make it a whole number (since x must also be a whole number).

The closest multiple of 50 less than \(522.5\) is \(500\), which would make \(y = 22.5\), but since y must be a whole number, let's try \(y = 50\):

\(49x - 50 = 522.5\)

\(49x = 572.5\)

\(x = \frac{572.5}{49}\)

\(x = 11.7\)

But x also needs to be a whole number because it represents rupees. So our assumption for y is incorrect. Let's try \(y = 100\) (the next multiple of 50):

\(49x - 100 = 522.5\)

\(49x = 622.5\)

\(x = \frac{622.5}{49}\)

\(x = 12.7\)

This still doesn't give us a whole number for x. We need to find values of y (in multiples of 50) that will make \(49x\) a whole number.

Let's try \(y = 150\):

\(49x - 150 = 522.5\)

\(49x = 672.5\)

\(x = \frac{672.5}{49}\)

\(x = 13.7\)

This is still not a whole number for x.

Let's try \(y = 200\):

\(49x - 200 = 522.5\)

\(49x = 722.5\)

\(x = \frac{722.5}{49}\)

\(x = 14.75\)

This gives us a decimal value for x, which is not possible for the amount in rupees.

We continue this process until we find whole numbers for both x and y.

Let's try \(y = 250\):

\(49x - 250 = 522.5\)

\(49x = 772.5\)

\(x = \frac{772.5}{49}\)

\(x =15.75 \)

This still doesn't work.

Let's try \(y=300\) paise or Rs.3:

\(49x -300=522.5 \)

Adding \(300\) to both sides gives us:

\(49x=822.5\)

Dividing both sides by \(49\) gives us:

\( x=16.7857...\)

This value of \( x \) is not an integer, so let's try increasing \( y \) further.

Continuing this process, if we try \(y=350\) paise or Rs.3.50:

\[49x-350=522.5 \]

Adding \(350\) to both sides gives us:

\[49x=872.5 \]

Dividing both sides by \(49\) gives us:

\[ x=17.8061...\]

This value of \( x \) is not an integer either.

We keep trying until we find an integer value for \( x \). Let's try with \(y=400\) paise or Rs.4:

\[49x-400=522.5 \]

Adding \(400\) to both sides gives us:

\[49x=922.5 \]

Dividing both sides by \(49\) gives us:

\[ x=18.8265306122...\]

This value of \( x \) is not an integer either.

We continue this process until we find an integer solution for both \( x \) and \( y \). Let's try with \(y=450\) paise or Rs.4.50:

\[49x-450=522.5 \]

Adding \(450\) to both sides gives us:

\[49x=972.5 \]

Dividing both sides by \(49\) gives us:

\[ x=19.84693877551...\]

This value of \( x \) is not an integer

Hope this helps you. Do mark me as brainlist.

Let's represent the initial amount the person has in rupees and paise as follows:

* Money initially = Rs. x + y/100

We are given that the person spent Rs. 10.45 and was left with Rs. 2y and 2x paise. We can represent this mathematically as:

* Money left = Rs. (2y + 2x)/100

Since the money spent is the difference between the initial amount and the money left, we can set up an equation:

* Rs. (x + y/100) - Rs. 10.45 = Rs. (2y + 2x)/100

Simplifying the equation and solving for x, we can find the initial amount the person had in rupees.

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