Answer :
Explanation:
Yes, the reaction between sulfuric acid (H2SO4) and sodium hydroxide (NaOH), which produces sodium sulfate (Na2SO4) and water (H2O), can be classified as both a neutralization reaction and a double displacement reaction.
**Neutralization Reaction:**
This reaction is primarily a neutralization reaction because it involves the combination of an acid (H2SO4) and a base (NaOH) to form water and a salt (Na2SO4). In this case:
- H2SO4 (acid) + 2NaOH (base) → Na2SO4 (salt) + 2H2O (water)
Here, sulfuric acid donates two hydrogen ions (H+) to hydroxide ions (OH-) from sodium hydroxide. This forms water (H2O), and the remaining ions (sulfate ion from H2SO4 and sodium ion from NaOH) combine to form sodium sulfate (Na2SO4).
**Double Displacement Reaction:**
The reaction can also be considered a double displacement reaction because the ions in the reactants exchange partners to form new compounds. Specifically:
- H+ (from H2SO4) combines with OH- (from NaOH) to form water (H2O).
- Na+ (from NaOH) combines with SO4^2- (from H2SO4) to form sodium sulfate (Na2SO4).
In double displacement reactions, the cations and anions of two different compounds switch places to form two new compounds. This process is evident in the given reaction where the sodium ion (Na+) from NaOH pairs with the sulfate ion (SO4^2-) from H2SO4 to produce sodium sulfate (Na2SO4), while the hydrogen ion (H+) from H2SO4 combines with the hydroxide ion (OH-) from NaOH to produce water (H2O).
Therefore, the reaction H2SO4 + 2NaOH → Na2SO4 + 2H2O is correctly termed both as a neutralization reaction (due to acid-base reaction producing salt and water) and a double displacement reaction (due to ions exchanging partners to form new compounds).
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