The distance between A and B is 490 km. A person travelled from ‘A’ to ‘B’ in 40 km/hr and started at 9 am, after one hour another person travelled from ‘B’ to ‘A’ at 50 km/hr. Then what time do they meet together?​

Answer :

Answer:

They meet at 03.00 pm

Step-by-step explanation:

Given that, The distance between A and B is 490 km.

Further given that, A person travelled from ‘A’ to ‘B’ in 40 km/hr and started at 9 am

So, Distance covered by first person in 1 hour = 40 km

So, Remaining distance to be covered = 490 - 40 = 450 km

Further given that, after one hour another person travelled from ‘B’ to ‘A’ at 50 km/hr at 10.00 am.

It means, both the person have to covered a distance of 450 km with their respective speeds of 40 km/hr and 50 km/hr.

So,

[tex]\sf\: Time\:taken = \dfrac{Distance}{ Speed_{(First\: person)} + Speed_{( Second\: person)} } \\ [/tex]

[tex]\sf\: Time\:taken = \dfrac{450}{ 40 + 50 } \\ [/tex]

[tex]\sf\: Time\:taken = \dfrac{450}{ 90 } \\ [/tex]

[tex]\implies\sf\:Time\:taken = 5 \: hours \\ [/tex]

Hence, They meet together after 5 hours, i.e they meet at 3 pm

Answer:10

Step-by-step explanation:

Other Questions