Answer:
To solve \( 3^{-2} \times 3^{-5} \), we can use the property of exponents that states \( a^m \times a^n = a^{m+n} \).
So, applying this property:
\[ 3^{-2} \times 3^{-5} = 3^{(-2) + (-5)} \]
Now, add the exponents:
\[ (-2) + (-5) = -7 \]
Therefore,
\[ 3^{-2} \times 3^{-5} = 3^{-7} \]
So, \( 3^{-2} \times 3^{-5} \) is equal to \( 3^{-7} \).