Answered

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In the given figure, rays OA, OB, OC and OD are such that
ZAOB
56°, ZBOC=100°, /COD = x° and ZDOA = 74°.
Find the value of x.
Hint. Sum of all the angles around a point is 360°.

solution
sum of all angle is 360 degree (given<aob=56

let the<cod be x°
ATQ
100+56+74+X=360(sum of all angle)
100+130+X=360
230+X=360
X= 360-230
X=130°(<COD)
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Answer :

sunshineallah9753

Answer:

Hi

Hope you are doing well and hope this helps you ☺️ ☺️ ☺️

Sure! Let's break it down step by step.

Given:

- ZAOB = 56°

- ZBOC = 100°

- ZCOD = x° (we need to find the value of x)

- ZDOA = 74°

We know that the sum of the angles around a point is 360°. So, sum of all angles around point O is:

ZAOB + ZBOC + ZCOD + ZDOA = 360

Substitute the given angles:

56 + 100 + x + 74 = 360

230 + x = 360

Now, solve for x:

x = 360 - 230

x = 130°

Therefore, the value of x is 130°.

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Have a nice day ahead dear✿⁠

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