Answer :
Answer:
Step-by-step explanation:
weight of box(1)= 19 1/2 kg
weight of box(2)= 33/4 kg
weight of box(3)= 16 1/2 kg
Postman carries them all means addition of all weights.
(19 1/2)+ (33/4)+ (16 1/2)
= 44 1/4 or 44.25
To find the total weight carried by the poster, we need to add the weights of the three boxes together. The weights given are:
1. First box: [tex]\bf 19 \frac{1}{2} kg[/tex]
2. Second box: [tex]\bf 33 \frac{3}{4} kg[/tex]
3. Third box: [tex]\bf 16 \frac{1}{2} kg[/tex]
Let's convert these mixed numbers into improper fractions for easier addition:
[tex]1. \: \: \: \: \bf19 \frac{1}{2} = 19 + \frac{1}{2} = \frac{38}{2} + \frac{1}{2} = \frac{39}{2} kg \\ 2. \: \: \: \: \bf33 \frac{3}{4} = 33 + \frac{3}{4} = \frac{132}{4} + \frac{3}{4} = \frac{135}{4} kg \\ 3. \: \: \: \: \bf16 \frac{1}{2} = 16 + \frac{1}{2} = \frac{32}{2} + \frac{1}{2} = \frac{33}{2} kg[/tex]
Now, add these fractions together to find the total weight:
[tex] \bf\[\frac{39}{2} + \frac{135}{4} + \frac{33}{2}\][/tex]
To add these fractions, we need a common denominator. The least common denominator of 2 and 4 is 4.
Convert each fraction:
[tex] \[\frac{39}{2} = \frac{39 \cdot 2}{2 \cdot 2} = \bf\frac{78}{4}\]\\\[\frac{135}{4} = \bf \frac{135}{4}\]\\\[\frac{33}{2} = \frac{33 \cdot 2}{2 \cdot 2} = \bf\frac{66}{4}\][/tex]
Now, add them together:
[tex] \bf\[\frac{78}{4} + \frac{135}{4} + \frac{66}{4} = \frac{78 + 135 + 66}{4} = \frac{279}{4}\][/tex]
Finally, convert 279/4 kg to a mixed number:
[tex]\[\frac{279}{4} = \bf69 \frac{3}{4} \text{ kg}\][/tex]
Therefore, the total weight carried by the poster is -
[tex] \boxed{ \bf69 \frac{3}{4} \text{ kg}} [/tex]