Answer:
To find the sum of 40 \frac{5}{6} + \frac{2}{3} 41, you need to have a common denominator. In this case, the least common multiple of 6 and 3 is 6.
So, you need to rewrite the fractions with a common denominator of 6:
40 \frac{5}{6} + \frac{2}{3} = \frac{5}{6} + \frac{4}{6} 41
Now that the fractions have a common denominator, you can add the numerators:
40 \frac{5}{6} + \frac{4}{6} = \frac{5+4}{6} = \frac{9}{6} 41
Finally, you can simplify the fraction by dividing both the numerator and denominator by their greatest common divisor, which is 3:
40 \frac{9}{6} = \frac{3 \times 3}{3 \times 2} = \frac{3}{2} 41
Therefore, the solution to 40 \frac{5}{6} + \frac{2}{3} 41 is 40 \frac{3}{2} 41 or 1.5 in decimal form.
Step-by-step explanation:
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