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Q.A ball is released from a height and it reaches the ground in 3s . if g = 9.8 ms^-2 , find height.

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Answer :

purnimagoswami

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Step-by-step explanation:

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GOURAVGAUTAM

Step-by-step explanation:

s = ut + 1/2 at^2

s = initial speed is zero than the value of ut is zero

now we have

1/2 at^2 put the values

0.5×9.8×3^2

4.9×9

44.1 is your answer

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