e. A farmer moves along the
boundary of a square field of side
10 m in 40 s. What will be the
magnitude of displacement of the
farmer at the end of 2 minutes 20
seconds from his initial position.

Answer :

Answer:140 Meters

Explanation:o determine the magnitude of displacement of the farmer, we start by calculating his speed.

Given:

Side length of the square field

=

10

s=10 m

Time taken to move along the boundary of the square field = 40 s

First, calculate the perimeter of the square field:

Perimeter

=

4

×

=

4

×

10

 m

=

40

 m

Perimeter=4×s=4×10 m=40 m

Next, calculate the speed of the farmer:

Speed

=

Distance

Time

=

40

 m

40

 s

=

1

 m/s

Speed=

Time

Distance

=

40 s

40 m

=1 m/s

Now, convert 2 minutes 20 seconds to seconds:

2

 minutes

+

20

 seconds

=

2

×

60

+

20

=

140

 seconds

2 minutes+20 seconds=2×60+20=140 seconds

Calculate the displacement using the formula:

Displacement

=

Speed

×

Time

Displacement=Speed×Time

Displacement

=

1

 m/s

×

140

 s

=

140

 m

Displacement=1 m/s×140 s=140 m

Therefore, the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position is

140

140

 meters.