Answer :
Explanation:
To form a quadratic polynomial with zeroes (a + 1) and (ß + 1) given that a and ß are the zeroes of the polynomial x² + 9x + 20, we can start by using Vieta's formulas.
Vieta's formulas state that for a quadratic polynomial ax² + bx + c with zeroes α and β, the sum of the roots is -b/a and the product of the roots is c/a.
Given that the zeroes of x² + 9x + 20 are a and ß, we know that a + ß = -9 and aß = 20.
Now, we need to find the new polynomial with zeroes (a + 1) and (ß + 1). To do this, we can use the fact that the sum of the new zeroes will be (a + 1) + (ß + 1) = a + ß + 2 = -9 + 2 = -7, and the product will be (a + 1)(ß + 1) = aß + a + ß + 1 = 20 + a + ß + 1 = 21.
Therefore, the new quadratic polynomial with zeroes (a + 1) and (ß + 1) is x² - (-7)x + 21, which simplifies to x² + 7x + 21.
Hope it helps you! Please mark my answer as a brainliest...
Answer:
first we do middle term factor of x²+9x+20 the factor are 4&5 and the find zero the zeros are 4&5 so alpha = 4 and Beta = 5 we put this equation (alpha + 1 ) ( beta ++ 1 )
E