Answer :
Answer:
To find the remainder when the polynomial \( t^3 - t^2 + 2t - 4 \) is divided by \( t - 1 \), we can use the Remainder Theorem. The Remainder Theorem states that the remainder of the division of a polynomial \( f(t) \) by \( t - c \) is \( f(c) \).
Here, \( f(t) = t^3 - t^2 + 2t - 4 \) and we are dividing by \( t - 1 \). According to the Remainder Theorem, the remainder is \( f(1) \).
To find \( f(1) \):
\[ f(1) = 1^3 - 1^2 + 2 \cdot 1 - 4 \]
\[ f(1) = 1 - 1 + 2 - 4 \]
\[ f(1) = 1 - 1 + 2 - 4 = -2 \]
Therefore, the remainder when \( t^3 - t^2 + 2t - 4 \) is divided by \( t - 1 \) is \(-2\).
Step-by-step explanation:
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Answer: -2
Step-by-step explanation:
t³ - t² + 2t -4 is when divide by t-1
So for zeros
t-1=0
t=1
on putting the value of t
(1)³ - (1)² + 2(1) - 4
1 - 1 + 2 - 4
3 - 5
-2
-2 is the remainder