Answer :
Step-by-step explanation:
Let's denote the number of mangoes Anil ate as \( x \).
According to the problem:
- Anil sold 40% more mangoes than he ate. This means he sold \( x + 0.4x = 1.4x \) mangoes.
- It's also given that he sold 70 mangoes.
So, we set up the equation:
\[ 1.4x = 70 \]
To find \( x \), divide both sides by 1.4:
\[ x = \frac{70}{1.4} \]
\[ x = 50 \]
Therefore, Anil ate \( \boxed{50} \) mangoes.
**Verification:**
- Anil sold 40% more than he ate, which is \( 1.4 \times 50 = 70 \).
- He indeed sold 70 mangoes, which matches the given information in the problem statement.
Thus, the solution is consistent and correct. Anil ate \( \boxed{50} \) mangoes.
Answer:
50
Step-by-step explanation:
ATQ, number of apples Anil sold = 40% more than number of apples Anil ate
i.e., number of apples Anil sold = number of apples Anil ate + 40% of number of apples Anil ate
Let x = number of apples Anil ate.
Thus, number of apples Anil sold = x+40/100*x = 140/100*x
i.e., 70=140/100*x
thus, x=70/140*100
x=50