Answer :
Answer:
3(ab²+bc²+ca²-a²b - b²c -c²a
Step-by-step explanation:
we apply:
(A-B)³=A³-B³-3AB(A-B)
Answer:
(a− b)³= a³− b³−3a²b + 3ab²
⟹(a − b)³= a³ − b³− 3ab(a−b)
Then,
(a−b)³ + (b− c)³ + (c − a)³
=(a³− 3a²b + 3ab²-b³) + (b³−3b²c + 3bc²− c³) + (c³− 3c²a + 3ca²− a³)
=−3a²b+ 3ab²− 3b²c + 3bc²− 3c²a+ 3ca²
=3a²(c−b) +3b² (a−c) + 3c²(b −a)