Answer:1/√3-√2
we have to rationalise the denominator
so multiply (√3+√2) to numerator and denominator
(1)(√3+√2) / (√3-√2) (√3+√2)
(a-b)(a+b)=a²-b²
so, (√3+√2)/(√3)²-(√2)²
(√3+√2)/3-2
so, (√3+√2) is the final answer
Step-by-step explanation:
1 - रूट 6 / √3
1/रूट 6 -√3 = 1-रूट 6 /√3
