Answer :
Answer:
If
p
=
2
−
a
then prove that
a
3
+
6
a
p
+
p
3
−
8
=
0
Given
p
=
2
−
a
to prove
a
3
+
6
a
p
+
p
3
−
8
=
0...
(
1
)
Now put the value of P in eq (1)
a
3
+
6
a
(
2
−
a
)
+
(
2
−
a
)
3
−
8
=
0
⇒
a
3
+
12
a
−
6
a
2
+
8
−
a
3
−
12
a
+
6
a
2
−
8
=
0
[
∴
(
a
−
b
)
3
=
a
3
−
b
3
−
3
a
2
b
+
3
a
b
2
]
⇒
0
=
0
(By eliminating equal terms we
have LHS = RHS)