Answer :
Answer:
The mismatch in voltage means the oven won't receive enough electrical energy to function correctly. The power it can draw at 220 V is far less than its designed power at 920 V, making it inefficient and underperforming.
Explanation:
If an electric oven rated at 3 kW and 920 V is operated on a standard domestic electric circuit of 220 V with a circuit rating of 10 A, several things can be analyzed:
1. **Power Rating and Voltage Mismatch**: The oven is designed to operate at 920 V. If it is connected to a 220 V supply, it will not receive sufficient voltage to operate properly. The power it draws will be significantly lower than its rated 3 kW because power is directly proportional to the square of the voltage (P ∝ V²) for a resistive load.
2. **Current Drawn by the Oven**: The rated power of the oven is 3 kW at 920 V. To find the current it draws at its rated voltage, we use:
\[
P = VI \implies I = \frac{P}{V} = \frac{3000 \text{ W}}{920 \text{ V}} \approx 3.26 \text{ A}
\]
This means the oven is designed to draw about 3.26 A at 920 V.
3. **Current Drawn at 220 V**: If the same oven is connected to 220 V, the current it draws can be determined by considering its resistance. The resistance \( R \) can be calculated using:
\[
R = \frac{V^2}{P} = \frac{920^2}{3000} \approx 282.13 \, \Omega
\]
Using this resistance to find the current at 220 V:
\[
I = \frac{V}{R} = \frac{220 \text{ V}}{282.13 \, \Omega} \approx 0.78 \text{ A}
\]
This current is within the limit of a 10 A rated domestic circuit.
4. **Power at 220 V**: The power consumed by the oven at 220 V can be calculated as:
\[
P = VI = 220 \text{ V} \times 0.78 \text{ A} \approx 172 \text{ W}
\]
This is much lower than its rated 3 kW, indicating it will not perform effectively.
### Conclusion
The oven will not operate properly if connected to a 220 V supply. It will draw significantly less power (about 172 W instead of 3000 W) and will not function as intended. Additionally, connecting a 920 V rated appliance to a 220 V supply is not safe or recommended. There is no danger of overloading the circuit because the current drawn (0.78 A) is well within the 10 A rating of the circuit. However, the oven will be underpowered and ineffective.
**Reason to justify the answer:** The mismatch in voltage means the oven won't receive enough electrical energy to function correctly. The power it can draw at 220 V is far less than its designed power at 920 V, making it inefficient and underperforming.