Solve for x
[tex] \sqrt{x + 2 \times ( \sqrt{x - 1}) } + \sqrt{x - 2 \times ( \sqrt{x - 1}) } = 2[/tex]
attach the solution with the answer

Answer :

Step-by-step explanation:

Certainly! Let’s solve the given equation step by step:

Distribute the terms inside the parentheses: [ x + 2(x - 1) + (x - 2)(x - 1) = 2 ]

Simplify each term: [ x + 2x - 2 + (x^2 - 3x + 2) = 2 ]

Combine like terms: [ x + 2x - 2 + x^2 - 3x + 2 = 2 ]

Rearrange the equation: [ x^2 - 2x + 2 = 2 ]

Subtract 2 from both sides: [ x^2 - 2x = 0 ]

Factor the left side: [ x(x - 2) = 0 ]

Now, we have two possible cases:

a) (x = 0) b) (x - 2 = 0)

For case (b), solve for (x): [ x - 2 = 0 ] [ x = 2 ]

Therefore, the solutions are (x = 0) and (x = 2)