Answer :
Answer:
1. 10m/s
Explanation:
To find the velocity of the ball after 3 seconds when thrown vertically upwards with an initial velocity of 40 m/s, we can use the equations of motion under constant acceleration (in this case, due to gravity):
Given:
- Initial velocity (u) = 40 m/s (upwards)
- Acceleration (a) = -9.8 m/s² (downwards, due to gravity)
- Time (t) = 3 seconds
We use the equation:
\[ v = u + at \]
Substitute the given values:
\[ v = 40 \, \text{m/s} + (-9.8 \, \text{m/s}²) \cdot 3 \, \text{s} \]
\[ v = 40 \, \text{m/s} - 29.4 \, \text{m/s} \]
\[ v = 10.6 \, \text{m/s} \]
The velocity of the ball after 3 seconds is approximately 10.6 m/s.
Therefore, the correct answer is:
\[ \boxed{10 \, \text{m/s}} \]
This matches option (1) in your list of answers.
Answer:
(1) 10 m/s
Explanation:
Every second 10-10 m/s is - so ans will be 10 m/Pl give Pls give me brilliant student