Answer :
Answer:
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Answer:
Please make me brainlist
Step-by-step explanation:
Here are five natural numbers that are multiples of 3:
1. 3
2. 6
3. 9
4. 12
5. 15
Let's calculate the cube of each number:
1. 3^3 = 27
2. 6^3 = 216
3. 9^3 = 729
4. 12^3 = 1728
5. 15^3 = 3375
Now, let's verify if these cubes are multiples of 27:
1. 27 = 27 × 1
2. 216 = 27 × 8
3. 729 = 27 × 27
4. 1728 = 27 × 64
5. 3375 = 27 × 125
Yes, the cube of each multiple of 3 is indeed a natural number that is a multiple of 27!