Answer:
8550
Step-by-step explanation:
Formula: [tex](a+b)^3=a^3+b^3+3ab(a+b)[/tex].
[tex]25^3 + (-19)^3 - 6^3 = 25^3 - (19^3 + 6^3) = (19+6)^3 - (19^3 + 6^3) = \\\\=(19^3 + 6^3 + 3\cdot 19\cdot 6\cdot (19+6))-(19^3 + 6^3) = 3\cdot 19\cdot 6\cdot (19+6)=\\\\=342\cdot 25 = (342\cdot 100):4 = 34200:4 = \boxed{\bf 8550}[/tex].
Answer:
If a+b+c = 0 then, a³+b³+ c² = 3abc it is the formula. so,(25)3+(-19)3+(-6)3 =
3x 25x-19×-6 = 8550.
