Answer :
Step-by-step explanation:
The greatest common divisor (GCD) of the three container capacities is 10 liters. This means that a container with a capacity of 10 liters can be used to measure the exact amount of milk in all three containers without any leftover milk.
| Container Capacity (L) |
|---|
| 20 |
| 30 |
| 60 |
| GCD |
In other words, you can fill the 10-liter container exactly twice to get 20 liters for container 1, fill it three times to get 30 liters for container 2, and fill it six times to get 60 liters for container 3.
Therefore, the maximum capacity of a container that can measure the milk in all three containers an exact number of times is 10 liters.
Answer:
The measurement of maximum capacity of a container that can measure the milk of the three containers exact number of times is 10 litres
Step-by-step explanation:
Given that, Three containers containing 20 litres, 30 litres and 60 litres of milk.
Now, we have to find the measurement of maximum capacity of a container that can measure the milk of the above containers exact number of times.
So, the measurement of maximum capacity of a container that can measure the milk of the above containers exactly is equals to HCF of (20, 30, 60)
To find HCF of (20, 30, 60), we use the method of prime factorization.
So, prime factorization are as
[tex]\sf\: Prime\:factors\:of\:20 = 2^2 \times 5 \\ [/tex]
[tex]\sf\: Prime\:factors\:of\:30 = 2 \times 3 \times 5 \\ [/tex]
[tex]\sf\: Prime\:factors\:of\:60 = {2}^{2} \times 3 \times 5 \\ [/tex]
Thus,
[tex]\implies\sf\:HCF (20, 30, 60) = 2 \times 5 = 10 \\ [/tex]
Hence,
The measurement of maximum capacity of a container that can measure the milk of the three containers exact number of times is 10 litres