Answer :
Answer:
ket 20 be x
here
on yt
@shubhbharadwaj2318
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hence y=21
Answer:
20
Step-by-step explanation:
To find the maximum capacity of a container that can measure the milk from three containers an exact number of times, we need to determine the highest common factor (HCF) of the capacities of the three containers.
Let's consider the capacities of the three containers:
1. Container 1: 20 liters
2. Container 2: 30 liters
3. Container 3: 60 liters
We'll find the prime factorization of each capacity:
1. 20 liters:
- Prime factorization of 20: \(20 = 2 \times 2 \times 5\)
2. 30 liters
- Prime factorization of 30: \(30 = 2 \times 3 \times 5\)
3. 60 liters:
- Prime factorization of 60: \(60 = 2 \times 2 \times 3 \times 5\)
Now, let's find the HCF by taking the common prime factors with their lowest powers:
- Common prime factors: 2 and 5
- Lowest power of 2: 2 (from 20 and 60)
- Lowest power of 5: 1 (from 20 and 30)
HCF = \(2^2 \times 5^1 = 20\) liters
Therefore, the maximum capacity of a container that can measure the milk from all three containers an exact number of times is 20 liters.