Answer:
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To find the momentum of the car and its direction, we follow these steps:
Given:
- Mass of the car, \( m = 2500 \) kg
- Velocity of the car, \( v = 54 \) km/h (in the north direction)
First, convert the velocity from km/h to m/s (since momentum is typically calculated using SI units):
\[ v = 54 \text{ km/h} \]
1 km/h = \( \frac{1000}{3600} \) m/s (conversion factor)
\[ v = 54 \times \frac{1000}{3600} \text{ m/s} = 15 \text{ m/s} \]
Now, calculate the momentum (\( p \)) of the car:
\[ p = m \times v \]
\[ p = 2500 \text{ kg} \times 15 \text{ m/s} \]
\[ p = 37500 \text{ kg m/s} \]
Therefore, the momentum of the car is \( 37500 \) kg m/s.
Direction:
- The car is moving in the north direction.
So, the momentum of the car is \( 37500 \) kg m/s in the north direction.
[tex] \huge \sf \purple{Answer:}[/tex]
37500 Kg•m/sec
[tex] \huge \sf \purple{Solution:}[/tex]
[tex] \small \bf \pink{Formula \: we'll \: use:} \\ \sf{p = mv \: \: \: \: }[/tex]
where p is momentum, m is mass and v is velocity!
[tex] \sf \gray{m = 2500 \: kg } \\ \sf \gray{v = 54 \: \frac{km}{h} } \: \: [/tex]
Conversion of units, [km/h to m/sec(SI)]
[tex] \sf \gray{v = 54 \frac{km}{h} = 15 \frac{m}{sec} }[/tex]
By using formula(mentioned above) ,
[tex] \sf{2500 \: kg\times15 \: \frac{m}{sec} } \\ \sf{ = 37500 \: kg \times \frac{m}{sec} }[/tex]
[tex] \huge \sf \purple{Thanks! }[/tex]
