Answer :

Step-by-step explanation:

To find the integral of \( e^{-5x} \), we use the standard integration technique for exponential functions. Here's the step-by-step process:

\[ \int e^{-5x} \, dx \]

1. Recognize that \( e^{-5x} \) is an exponential function where the exponent is a linear function of \( x \).

2. Use the formula for integrating an exponential function of the form \( e^{ax} \):

\[

\int e^{ax} \, dx = \frac{1}{a} e^{ax} + C

\]

where \( a \) is a constant and \( C \) is the constant of integration.

3. In this case, \( a = -5 \).

4. Substitute \( a \) with \(-5\) in the formula:

\[

\int e^{-5x} \, dx = \frac{1}{-5} e^{-5x} + C

\]

5. Simplify the result:

\[

\int e^{-5x} \, dx = -\frac{1}{5} e^{-5x} + C

\]

So, the integral of \( e^{-5x} \) with respect to \( x \) is:

\[

-\frac{1}{5} e^{-5x} + C

\]

Answer:

Here are five different ways to get each of the specified answers using sums or products of two or more integers:

### (a) -6

1. \( -4 + (-2) = -6 \)

2. \( -10 + 4 = -6 \)

3. \( 2 + (-8) = -6 \)

4. \( 3 \times (-2) = -6 \)

5. \( -3 \times 2 = -6 \)

### (b) -1

1. \( 0 + (-1) = -1 \)

2. \( 2 + (-3) = -1 \)

3. \( -4 + 3 = -1 \)

4. \( -1 + 0 = -1 \)

5. \( -2 \times \frac{1}{2} = -1 \)

### (c) +8

1. \( 5 + 3 = 8 \)

2. \( 10 + (-2) = 8 \)

3. \( 2 \times 4 = 8 \)

4. \( 16 \div 2 = 8 \)

5. \( -1 + 9 = 8 \)

### (d) +4

1. \( 2 + 2 = 4 \)

2. \( 6 + (-2) = 4 \)

3. \( 1 + 3 = 4 \)

4. \( 2 \times 2 = 4 \)

5. \( 8 \div 2 = 4 \)

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