Answer :
Step-by-step explanation:
To find the integral of \( e^{-5x} \), we use the standard integration technique for exponential functions. Here's the step-by-step process:
\[ \int e^{-5x} \, dx \]
1. Recognize that \( e^{-5x} \) is an exponential function where the exponent is a linear function of \( x \).
2. Use the formula for integrating an exponential function of the form \( e^{ax} \):
\[
\int e^{ax} \, dx = \frac{1}{a} e^{ax} + C
\]
where \( a \) is a constant and \( C \) is the constant of integration.
3. In this case, \( a = -5 \).
4. Substitute \( a \) with \(-5\) in the formula:
\[
\int e^{-5x} \, dx = \frac{1}{-5} e^{-5x} + C
\]
5. Simplify the result:
\[
\int e^{-5x} \, dx = -\frac{1}{5} e^{-5x} + C
\]
So, the integral of \( e^{-5x} \) with respect to \( x \) is:
\[
-\frac{1}{5} e^{-5x} + C
\]
Answer:
Here are five different ways to get each of the specified answers using sums or products of two or more integers:
### (a) -6
1. \( -4 + (-2) = -6 \)
2. \( -10 + 4 = -6 \)
3. \( 2 + (-8) = -6 \)
4. \( 3 \times (-2) = -6 \)
5. \( -3 \times 2 = -6 \)
### (b) -1
1. \( 0 + (-1) = -1 \)
2. \( 2 + (-3) = -1 \)
3. \( -4 + 3 = -1 \)
4. \( -1 + 0 = -1 \)
5. \( -2 \times \frac{1}{2} = -1 \)
### (c) +8
1. \( 5 + 3 = 8 \)
2. \( 10 + (-2) = 8 \)
3. \( 2 \times 4 = 8 \)
4. \( 16 \div 2 = 8 \)
5. \( -1 + 9 = 8 \)
### (d) +4
1. \( 2 + 2 = 4 \)
2. \( 6 + (-2) = 4 \)
3. \( 1 + 3 = 4 \)
4. \( 2 \times 2 = 4 \)
5. \( 8 \div 2 = 4 \)