Answer :
Answer:
Step-by-step explanation:
Given, AP of form [tex]\frac{3}{5}n+3[/tex].
We know that, nth term of AP is:
[tex]a_n=a+(n-1)d = a+nd-d=(d)n+(a-d)[/tex]
Comparing, it follows:
[tex](d)n=\frac{3}{5}n\\\implies d = \frac{3}{5}[/tex]
Also,
[tex]a-d=3\\a = 3+d\\a = 3+\frac{3}{5} = \frac{16}{5}[/tex]
Answer:
let n be s
so the common difference will be
s=n/2 a+n-1d
d=5/3