Answer :

Answer:

Step-by-step explanation:

Given, AP of form [tex]\frac{3}{5}n+3[/tex].

We know that, nth term of AP is:

[tex]a_n=a+(n-1)d = a+nd-d=(d)n+(a-d)[/tex]

Comparing, it follows:

[tex](d)n=\frac{3}{5}n\\\implies d = \frac{3}{5}[/tex]

Also,

[tex]a-d=3\\a = 3+d\\a = 3+\frac{3}{5} = \frac{16}{5}[/tex]

Answer:

let n be s

so the common difference will be

s=n/2 a+n-1d

d=5/3

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