Answer :
Answer:
To find different solutions for the quadratic equation \( y = ax^2 + bx + c \), we can plug in various values of \( x \) and compute \( y \) based on given values of \( a \), \( b \), and \( c \). Here are six different possible solutions:
Let's assume the values of \( a = 1 \), \( b = 0 \), and \( c = 0 \) for simplicity. This choice makes the solutions straightforward and easy to compute.
\[ y = x^2 \]
Now, we will compute \( y \) for the given values of \( x \):
| \( x \) | \( y = x^2 \) |
|--------|--------------|
| 0 | 0 |
| 1 | 1 |
| 2 | 4 |
| 3 | 9 |
| -1 | 1 |
| -2 | 4 |
| -3 | 9 |
So, the table of solutions for \( y = x^2 \) with the values of \( x \) given is:
| \( x \) | \( y = x^2 \) |
|--------|--------------|
| 0 | 0 |
| 1 | 1 |
| 2 | 4 |
| 3 | 9 |
| -1 | 1 |
| -2 | 4 |
| -3 | 9 |
These values represent different solutions to the quadratic equation \( y = x^2 \).