Answer :
Answer:
Let's denote the original amount of money intended for distribution between M and N as
9
9x (since the ratio of distribution was 4:5, and 4 + 5 = 9 parts).
According to the problem, due to incorrect distribution, the money was distributed among M, N, and P in the ratio 3:2:1. Hence, the total parts in this distribution ratio are
3
+
2
+
1
=
6
3+2+1=6 parts.
Let the actual amounts received by M, N, and P be
3
3y,
2
2y, and
y respectively. Then we have:
3
+
2
+
=
9
3y+2y+y=9x
6
=
9
6y=9x
=
9
6
=
3
2
y=
6
9x
=
2
3x
From the problem, M gained 5,000 due to this incorrect distribution. Therefore, M's gain is
3
−
4
=
5000
3y−4x=5000.
Substituting
=
3
2
y=
2
3x
into the equation gives:
3
(
3
2
)
−
4
=
5000
3(
2
3x
)−4x=5000
9
2
−
4
=
5000
2
9x
−4x=5000
9
−
8
2
=
5000
2
9x−8x
=5000
2
=
5000
2
x
=5000
=
2
×
5000
=
10000
x=2×5000=10000
Now, we can find the total amount distributed originally:
9
=
9
×
10000
=
90000
9x=9×10000=90000
Therefore, the total amount distributed was
90000
90000