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three unbaised coin are tossed once .what is the probability of getting at least two heads.

Answer :

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Solution :
The sample space that can be constructed as follows
s={  TTT,TTH,THT,THH,HTT,HTH,HHT,HHH  }
T- denotes tail
H - denotes head
now ,
n( s ) = 8

Let P denote the event of getting atleast 2 heads
{ THH,HTH,HHT,HHH }

n(P) = 4

Probability of at least 2 heads = n(P) /n(s)
                                           = 4/8
                                           = 1/2
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