Answer :
[tex]dy/dx = \frac{1}{\sqrt{1-(3Sinx+4cosx/5)^2}}*(3 cosx -4sinx/5)[/tex]
Answer:
1
Explanation:
y=sin^-1(3/5.sinx+4/5.cosx)
put 3/5=cosA &4/5=sinA
tanA=4/3
hence A =tan^-1(4/3)
now,
y=sin^-1(cosA.sinx+sinA.cosx)
y=sin^-1[sin(A+x)]
means y=A+x
but A=tan^-1(4/3)
y=tan^-1(4/3)+x
now,
diff.w.r.t.x
dy/dx= 0+1
dy/dx=1