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a man walks 3 km north and then 4 km east find how far is he now from the starting position

Answer :

Using Pythagoras theorem  [tex] \sqrt{4^2+3^2} [/tex] = 5 km
H =  P sq.  +B sq.

Therefore

19 + 16 = 25

Therefore he is 5 km far from his starting position.

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